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Using Cramer's Rule, what is the value of x in the solution to the system of equations below?

-X-3y = -3
-2x-5y=-8

Respuesta :

Answer:

B)

|-3 -3|

|-8 -5|

——— =9

-1

Step-by-step explanation:

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The value of x in the solution to the system of equations using Cramer's rule is 9.

What is a linear equation?

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

If in the linear equation one variable is present then the equation is known as the linear equation in one variable.

We have two linear equations:

-x - 3y = -3

-2x -5y = -8

According to Cramer's rule, we have to make matrices such that:

[tex]\rm D_x=\left[\begin{array}{ccc}-3&-3\\-8&-5\\\end{array}\right][/tex]

[tex]\rm D_y=\left[\begin{array}{ccc}-1&-3\\-2&-8\\\end{array}\right][/tex]

[tex]\rm D=\left[\begin{array}{ccc}-1&-3\\-2&-5\\\end{array}\right][/tex]

To find the value of x we must find the value of the determinants for the above matrices.

[tex]\rm |D_x| = (-3)(-5)-(-8)(-3) \Rightarrow -9[/tex]

[tex]\rm |D| = (-1)(-5)-(-2)(-3) \Rightarrow -1[/tex]

[tex]\rm x =\frac{|D_x|}{|D|}[/tex]

[tex]\rm x = \frac{-9}{-1}[/tex]

x = 9 and

For the value of y

[tex]\rm |D_y| = (-1)(-8)-(-2)(-3) \Rightarrow 2[/tex]

[tex]\rm |D| = (-1)(-5)-(-2)(-3) \Rightarrow -1[/tex]

[tex]\rm y =\frac{|D_y|}{|D|}[/tex]

[tex]\rm y = \frac{2}{-1}[/tex]

y = -2 and

Thus, the value of x in the solution to the system of equations using Cramer's rule is 9.

Learn more about the linear equation here:

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