Question

wo people on skates, one with a mass of 61 kg and the other with a mass of 40 kg, stand on ice (frictionless surface) holding a 10 m pole (negligible mass). The skaters pull themselves from the end of the pole until they meet. How far does the 40 kg skater move. Answer:

Answer 1

Answer:

x=6.19m

Explanation:

Let m1, m2 be the two masses

and x the distance moved by mass 65kg

Therefore:- distance two=10-x

$\\m_{1}x_{1}=m_{2}x_{2}\\(65*x)=40(10-x)\\=>65x=400-40x\\x=3.81\\Therefore:- \\(10-x)=10-3.81=6.19$