Question

What will be the output after the following code is executed? def pass_it(x, y): z = y**x return(z) num1 = 3 num2 = 4 answer = pass_it(num1, num2) print(answer)

Answer 1

Answer:

"64" is the output of the above code.

Explanation:

• The function holds the expression with (**) operator which is used to calculate the power in python language.
• So if we write 2**4, then this will give 16 as output. It is because when we calculate the $2^{4}$, then it will become 16.
• The above question passes the num1 and num2 value in the function as an argument which is 3 and 4.
• So 3 will be initialized for x variable and 4 is for y variable.
• So when we calculate $y^{x}$ then it will become $4^{3}$ which will become 16.
• So 64 is the output for the above question.

Answer 2

The output of a program are the code segments that are executed by the print statements of the program.

The output of the given code after execution is 64

The program is meant to return the nth power of a number.

The numbers passed to the pass_it function from the main function are 3 and 4,

The program is meant to return num2^num1.

This is represented as 4^3

4^3 is 64.

Hence, the output of the given code after execution is 64

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