Answer:
The answer is: 51.8 g (86% of serving size)
Explanation:
In order to solve the problem, we have to first determine the number of moles there are in 11.0 g of sucrose. Sucrose has a molecular weight of 342 g (we calculate this from the molar mass of the elements : 12 x 12 g/mol C + 22 x 1 g/mol H + 11 x 16 g/mol O). So, we divide the mass (11.0 g) into the molecular weight of sucrose:
11.0 g sucrose x 1 mol/342 g sucrose= 0.032 mol
We have 0.032 mol of sucrose in a serving of 60 g. But we need less moles (0.0278 mol):
0.032 mol ------------ 60 g serving
0.0278 mol------------ x= 0.0278 mol x 60 g serving/0.032 mol
x= 51.8 g
So, lesser than 1 serving of 60 g must be eaten to consume 0.0278 mol os sucrose. Exactly, 51.8 g (which stands for a 86% of the serving size).
When the servings of this cereal must be eaten to consume 0.0278 moles of sugar is 51.8 g (86% of serving size)
To solve the situation, we have to willingly define the number of moles there are in 11.0 g of sucrose. When the Sucrose has a molecular weight of 342 g (we compute this from the molar mass of the elements is: 12 x 12 g/mol C + 22 x 1 g/mol H + 11 x 16 g/mol O). After that, we divide the mass (11.0 g) into the molecular weight of sucrose:
Then 11.0 g sucrose x 1 mol/342 g sucrose= 0.032 mol
Now, We have 0.032 mol of sucrose in a serving of 60 g. But we require fewer moles (0.0278 mol):
Then 0.032 mol ------------ 60 g serving
Then 0.0278 mol------------ x= 0.0278 mol x 60 g serving/0.032 mol
Hence, x is = 51.8 g
Therefore, lesser than 1 serving of 60 g must be eaten to consume 0.0278 mol of sucrose. Precisely, 51.8 g (which stands for 86% of the serving size).
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