Question

Please please help me! :)

Answer 1

Answer:

$x=[-3],[-2],[-2],[2],[3]$

Explanation:

According to the Fundamental Theorem of Algebra, any polynomial of degree n has n roots  that are complex numbers. In order to solve this problem, let's plot this polynomial. Remember that the zeros of a function f(x) are those x-values at which y = 0, in other words, the x-intercepts. So from the figure below, we have that the zeros are:

$x=-3 \\ \\ x=-2 \ \text{Multiplicity 2} \\ \\ x=2 \\ \\ x=3$

So arranging from smallest to largest, since -2 is a double root we list it twice:

$x=[-3],[-2],[-2],[2],[3]$