Answer:
Answer is 257°C
Explanation:
Given
frequency = 628 Hz
wavelength = 0.49 m
speed of sound at 0°C = 325 m/s
Find
1.speed of sound at t °C=?
2.temperature = ?
Formula
speed of sound at t °C = speed of sound at 0°C [1+t/273]
Solution
1. speed of sound at t °C = f*∧
= 628*0.49
=307.7m/s
2.speed of sound at t °C = speed of sound at 0°C [1+t/273]
307.7 m/s = 325 m/s [1+ t/ 273]
307.7/325 = 1+t/273
0.94 = 1+t/273
multiplying 273 on both sides
(0.94)(273) = 1+t/273 (273)
258 = 1+ t
258 - 1 = t
257°C = t