Question

find the start and end coordinates of y=2 sin x.

Answer 1

Answer:

Step-by-step explanation:

when x=0

y=2 sin 0=2×0=0

when x=π/2

y=2×sin (π/2)=2×1=2

when x=π

y=2 sin π=2×0=0

when x=3π/2

y=2 sin (3π/2)=2×-1=-2

when x=2π

y=2 sin (2π)=2×1=2

$if ~0\leq x\leq 2\pi \\initial ~point~is ~(0,2)\\end~point~is ~(2\pi ,0)$