Respuesta :
Answer:
[tex](n+2)^2+6[/tex]
Step-by-step explanation:
The picture of the question in the attached figure
we know that
In the pattern 1 there are
[tex]small\ squares=(3^2+6)=15[/tex]
In the pattern 2 there are
[tex]small\ squares=(4^2+6)=22[/tex]
In the pattern 3 there are
[tex]small\ squares=(5^2+6)=31[/tex]
we can write the expression in the form
[tex](n+a)^2+b[/tex]
where
[tex]a=2\\b=6[/tex]
substitute
[tex](n+2)^2+6[/tex]
An expression for the number of small squares in pattern n is [tex](n+2)^{2}+6[/tex] .
In the pattern 1:
3 + (3 x 3) + 3 = 15
Number of small squares = 15
In the pattern 2:
3 + (4 x 4) + 3 = 22
Number of small squares = 22
In the pattern 3:
3 + (5 x 5) + 3 =31
Number of small squares = 31
In the pattern n:
[tex]3+(n+2)^{2} +3[/tex]
Simplify:
[tex]=(n+2)^{2}+6[/tex]
Therefore, an expression for the number of small squares in pattern n is [tex](n+2)^{2}+6[/tex] .
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