Question

Use the Remainder Theorem to find the remainder for (4x^3+4x^2+2x+3)/(x-1) and state whether or not the binomial is a factor of the polynomial.

Answer 1

Answer:

Step-by-step explanation:

x-1=0

x=1

4(1)³+4(1)³+2(1)+3=4+4+2+3=13≠0

so binomial is not a factor.

Answer 2

The remiander is not a factor of the polynmial because the value of our remainder is not equal to zero,

Determine whether the remainder is a factor of the polynimial

Using Polynomial Remainder Theorem to find the remainder

The Divisor is (x-1) therefore x = 1

Inputting the value of x into the main equation (quotient) to find the remainder and to check whether the binomial is a factor of the polynomial.

(4$x^{3}$ + 4$x^{2}$ + 2$x$ + 3)

4($1^{3}$) + 4($1^{2}$) + 2($1$) + 3

4 + 4 + 2 + 3 = 13

13 ≠ 0

we can conclude that Because the value of our remainder is not equal to zero, the divisor is not  a factor of the polynomial

learn more about Polynomials : brainly.com/question/2416165