Question

0.9+{[3.25−(6 9/16 −0.025y)·0.6]÷0.75}÷6 2/3 =1.2 solve for y
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Answer 1

Answer:

$y = \dfrac{875}{6}$

Step-by-step explanation:

We use the PEMDAS rule, meaning the order of priority is parenthesis, Multiplication, Division, Addition, and Subtraction.

With PEMDAS, let us simply the equation

$0.9+[[3.25-(6+9/16-0.025y)*0.6]\div 0.75] \div 6 \dfrac{2}{3} =1.2$

First let us simplify the parenthesis $()$ and get:

$0.9+[[3.25-(6.5625-0.025y)*0.6]\div 0.75] \div 6 \dfrac{2}{3} =1.2$

and multiply what is in $()$ by $-1$ and  $0.6$ to get:

$0.9+[[3.25-3.9375+0.015y]\div 0.75] \div 6 \dfrac{2}{3} =1.2$

$0.9+[[-0.6875+0.015y]\div 0.75] \div 6 \dfrac{2}{3} =1.2$

Now we divide what is in $[]$ by 0.75 to get:

$0.9+[-0.91667+0.02y] \div 6 \dfrac{2}{3} =1.2$

and we divide $[]$ by $6 \dfrac{2}{3}$  and get:

$0.9-\dfrac{11}{80} +\dfrac{3}{1000}y =1.2$

simplifying gives us

$\dfrac{61}{80} +\dfrac{3}{1000}y =1.2$

$\dfrac{3}{100}y =\dfrac{7}{16}$

$\boxed{y = \dfrac{875}{6} }$