Question

I am trying to get the radius of this equation.
x²+y²-11y+28=0
The subject is writing equations of circles in standard form using properties.

Answer 1

Answer:

Step-by-step explanation:

x^2 + y^2 - 11y + 28 = 0

x^2 + y^2 - 11y + (11/2)^2 = -28 + (11/2)^2

x^2 + (y - 11/2)^2 = 2.25

so, it's a circle with center at (0,5.5) with radius 1.5