this hanger is in balance. there are 2 labeled weights of 4 grams and 12 grams the 3 circles have the same weight. what is the weight of each circle.

Answer:
8/3
Step-by-step explanation:
3x+4=12
find what x equals
subtract 4 on both sides (+4-4=0) (12+4=16)
then we have 3x=16
divide 16 by 3 = 8/3 (simplest form)
check- 3(8/3) + 4=12
^=8+4=12
^=12=12 so the answer is 8/3 i hoped this helped!
The hanger is in a balanced state then the weight of each circle is 8/3.
This hanger is in balance. there are 2 labeled weights of 4 grams and 12 grams the 3 circles have the same weight.
What is the weight of each circle?
Let the weight of each circle be x.
This hanger is in balance. there are 2 labeled weights of 4 grams and 12 grams the 3 circles have the same weight.
Left hand side weight = x+ x + x+ 4 = 3x+4
Right hand side weight = 12
Then,
The hanger is in a balanced state, the weight of each circle is given by,
The weight of the left-hand side = the weight of the right-hand side
[tex]\rm 3x+4 = 12\\\\3x =12-4\\\\3x = 8\\\\x = \dfrac{8}{3}[/tex]
The value of x is 8/3.
Hence, The weight of each circle is 8/3.
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