[tex]$ PS = \frac{4}{3} x[/tex]
Solution:
Given PRQ is a triangle.
ST is a line parallel to RQ.
[tex]$PT = x, \ PQ = 3x, \ SR=\frac{8}{3}x[/tex]
[tex]TQ=PQ-PT[/tex]
[tex]TQ=3x -x=2x[/tex]
Triangle proportionality theorem,
If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.
[tex]$\frac{PS}{SR} =\frac{PT}{TQ}[/tex]
[tex]$\frac{PS}{\frac{8}{3} x} =\frac{x}{2x}[/tex]
Do cross multiplication, we get
[tex]$ PS \times 2x=x \times \frac{8}{3} x[/tex]
Divide by 2x on both sides, we get
[tex]$ PS = \frac{4}{3} x[/tex]