Answer:
The answer to your question is below
Explanation:
Data
Stock solution concentration = 0.00190 M
Volume stock solution = 10 ml
Final volume = 100 ml
Standard solution concentration = ?
Absorbance of the standard solution = 0.62
Process
A) 0.00190 M it was given in the data
B) 0.62 it was given in the data
C) C1V1 = C2V2
C2 = C1V1/V2
C2 = (0.00190)(10)/100
C2 = 0.000190 M
D) Ratio = Absorbance/Concentration = 0.62/0.000190
= 3263.2
