Question

x^2+(y+1)^2=4^2 a formula general
ES URGENTEEEEEE
grax<3

Answer 1

Answer:

circle  centered at (0,-1) and radius 4.

Step-by-step explanation:

The equation of a circle of radius r, with center is (a,b) is

(x-a)^2+(y-b)^2=r^2.

x^2+(y+1)^2=4^2=(x-0)^2+(y-(-1))^2=4^2 so that a=0, b--1 and r=4.