9. A student observed the following reaction:
AICI(aq) + 3NaOH(aq) →
Al(OH),(s) + 3NaCl(aq)
After the products were filtered, which
substance remained on the filter paper?
(1) NaCl (3) AICI,
(2) NaOH (4) Al(OH),​

Respuesta :

Answer:

The substance that remained on the filter paper is Al(OH).

Explanation:

  • Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
  • So in our experiment the product formed is aluminum hydroxide Al(OH)   and sodium chloride (NaCl).
  • Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
  • Hence aluminum hydroxide being only solid product remains on the filter paper.
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