To do with COS, TAN and SIN

Answer:
Step-by-step explanation:
[tex]\frac{AB}{BC} =cos 71\\BC=\frac{AB}{cos 71} =\frac{6.3}{cos71} \approx 19.351[/tex]
The answers are BC = 6.3/ cos71 = 19.351 and BC = 6.3 / sin 19 = 19.351
Step-by-step explanation:
cosB = [tex]\frac{base}{hypoteneus}[/tex]
or, cos 71 = [tex]\frac{AB}{BC}[/tex]
or,BC = [tex]\frac{AB}{cos71}[/tex]
= 6.3/ cos71 = 19.351
Here, ∠C = 180 - (90 + 71 ) = 19
sin19 =[tex]\frac{perpendicular}{hypoteneus}[/tex]
or, sin 19 = AB/ BC
or, BC = AB /sin 19
= 6.3 / sin 19 = 19.351
We cannot find BC in terms of tan as tan means perpendicular/ hypotenuse. BC is the hypotenuse and that is got eliminated.
Here is the explanation.