Answer:
1) [tex]90m^3[/tex]
2) 16 m
Explanation:
1)
The hole in the ground has the shape of a prism, so its volume can be calculated as the volume of a prism:
[tex]V=lwh[/tex]
where:
l is the length
w is the width
h is the height of the prism
For the hole in this problem, we have:
l = 5 m (length)
w = 3 m (width)
h = 6 m (height)
Therefore, the volume of the hole (and of earth removed) is
[tex]V=5\cdot 3 \cdot 6 =90 m^3[/tex]
2)
The base of the room in this problem has the shape of a rectangle, so we can write its area s
[tex]A=lw[/tex]
where:
l is the length
w is the width (breadth)
For the room in this problem, we have:
[tex]A=96 m^2[/tex] is the area of the base of the room
w = 6 m (breadth)
Therefore, the length of the room can be found by re-arranging the equation:
[tex]l=\frac{A}{w}=\frac{96}{6}=16 m[/tex]