Which of the following represents gamma emission?


3015P Imported Asset 3014Si + ___


23892U Imported Asset 23490Th + ___


147N + 42He Imported Asset 178O + ___


13153I Imported Asset 13153I + _

Respuesta :

Answer:

       [tex]^{238}_{92}U\rightarrow ^{234}_{90}Th+^4_2{He}+^0_0\gamma[/tex]

Explanation:

The equations are:

    [tex]^{30}_{15}P\rightarrow^{30}_{14}Si+[/tex] ____

    [tex]^{238}_{92}U\rightarrow ^{234}_{90}Th+[/tex] ____

   [tex]^{14}_{7}N+ ^{4}_{2}He+\rightarrow ^{17}_{8}O+[/tex] ____

    [tex]^{131}_{53}I\rightarrow ^{131}_{53}I+[/tex] ____

You need to add a particle to balance either the mass number (the superscript to the left of the chemical symbol) or the atomic number (the subscript to the left of the chemical symbol).

These are the particles for each of the equations:

1.   [tex]^{30}_{15}P\rightarrow^{30}_{14}Si+^0_{1}\beta[/tex]

This is a typical radioactive decay: the emission of a positron, whith the decrase of the atomic number.

2.    [tex]^{238}_{92}U\rightarrow ^{234}_{90}Th+^4_2{He}+^0_0\gamma[/tex]

This is alpha uranium decay and it implies the emission of the alfa particles and gamma emmission. It is a highly energetic nuclear reaction.

   [tex]^4_2He[/tex] is the alpha particle

  [tex]^0_0\gamma[/tex] represent gamma emission.

Gamma emission is just electromagnetic radiation of high energy. They do not change either the mass number or the atomic number.

3. [tex]^{14}_{7}N+ ^{4}_{2}He+\rightarrow ^{17}_{8}O+^1_1H[/tex]

This is the emission of a proton, with low energy release.

4. [tex]^{131}_{53}I\rightarrow ^{131}_{53}I[/tex]

There is not any change.

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