Question

A 12.0 kg package in a mail-sorting room slides 2.00 m down a chute that is inclined at 55∘ below the horizontal. The coefficient of kinetic friction between the package and the chute's surface is 0.20.

Answer 1

Answer:

Net Force= 165.68J

Explanation:

Here is the complete question

A 12.0-kg package in a mail-sorting room slides 2.00 m down a chute that is inclined at 55.0∘ below the horizontal. The coefficient of kinetic friction between the package and the chute’s surface is 0.20. Calculate the work done on the package by (a) friction, (b) gravity, and (c) the normal force. (d) What is the net work done on the package?

F=μkN

F= μkMgcos55

F=0.2*12*9.8*0.5736

F= 13.49N

Work done by package by friction

Wf=Ffscoso

=13.49*2*(-1)

= -29.98J

Work done by gravity

Wg= FgscosO

Mgscos[90-55]

=12*9.8*2*0.8191

=192.66J

Work done by normal force

Wn= FnScos90

0J

Net Force= Wf+Wg+Wn

=-26.98+192.66+0

=165.68J

Answer 2

Answer:(a) -26.98J (b) 192.66J (c) 0J (d) 165.68J

The complete question is given below

A 12.0 kg package in a mail-sorting room slides 2.00 m down a chute that is inclined at 55∘ below the horizontal. The coefficient of kinetic friction between the package and the chute's surface is 0.20. Calculate the work done on the package by (a) friction, (b) gravity, and (c) the normal force. (d) What is the net work done on the package?

Explanation: Please see the attachments below