Answer:
0.9666
Step-by-step explanation:
Given that a manufacturing facility has 21 high pressure valves manufactured by Company A and 14 valves manufactured by Company B.
6 valves are chosen at random
Total no of ways of randomly choosing 6 valves = (21+14)C6
=[tex]35C6 = \frac{35*34*33*32*31*30}{6!} \\=1623160[/tex]
Choosing 5 or fewer form company A can be as follows
(A,B) = (0,6) (1,5) (2,4)(3,1)(4,2) (5,1)
This can be written as 1-Prob of choosing all 6 from A
No of ways of choosing all 6 from A = 21C6 = 54264
Hence the probability that 5 or fewer are from Company A
=[tex]1-\frac{54264}{1623160} \\=1-0.0334\\=0.9666[/tex]
