Answer:
162500000.
Explanation:
Given that
Diameter of the wire , d= 1.8 mm
The length of the wire ,L = 15 cm
Current ,I = 260 m A
The charge on the electron ,e= 1.6 x 10⁻¹⁹ C
We know that Current I is given as
[tex]I=\dfrac{q}{t}[/tex]
I=Current
q=Charge
t=time
q= I t
q= 260 m t
The total number of electron = n
q= n e
[tex]n=\dfrac{260\times 10^{-3}\ t}{1.6\times 10^{-9}}[/tex]
n=162500000 t
[tex]\dfrac{n}{t}=16250000[/tex]
The number of electron passe per second will be 162500000.
