Question

A laboratory stock solution is 1.50 M NaOH. Calculate the volume of this stock solution that would be needed to prepare 300. mL of 0.200 M NaOH. a. 2.25 mL b. 10.0 mL c. 40.0 mL d. 1.0 mL e. 0.100 mL

Answer 1

Answer:

Option c. 40 mL

Explanation:

Dilution formula:

M Concentrated . Concentrated Volume = Diluted volume . M diluted

1.50 M . Concentrated volume = 300 mL . 0.200 M

Concentrated volume = (300 mL . 0.200 M) / 1.50 M

Concentrated volume = 40 mL

When the dilution factor is applied, it is indicated how many times a concentration is diluted to obtain a lower solute concentration, so its concentration depends on the number of solute particles and the total volume

Answer 2

Answer: Option (c) is the correct answer.

Explanation:

The given data is as follows.

       $M_{1}$ = 1.50 M,     $V_{1}$ = ?

       $M_{2}$ = 0.2 M,     $V_{2}$ = 300 ml

Now, we will calculate the value of $V_{1}$ as follows.

             $M_{1}V_{1} = M_{2}V_{2}$

            $1.50 \times V_{1} = 0.2 \times 300$

                  $V_{1}$ = 40 ml

Thus, we can conclude that volume of this stock solution that would be needed to prepare 300 mL of 0.200 M NaOH is 40 ml.