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A motorcycle of weight 1.9 kN accelerates from 0 to 87.4 km/h in 5.2 s. What are the magnitudes of (a) the constant acceleration and (b) the net force causing the acceleration?

Respuesta :

Answer:

(a) 4.67m/s^2

(b) 887.3N

Explanation:

The speed is given in km/h ,therefore we have to convert it to m/s

In doing so 87.4km/h = 87.4×1000/3600

=24.28m/s

Constant acceleration is defined as the ratio is velocity per unit time

Constant acceleration = velocity/time

= 24.28/5.2

=4.67m/s^2

The net force causing the acceleration

The weight of the motorcycle is 1.9kN

Giving us a mass of 1900/10

= 190kg

Therefore the net force .= m×a

= 190 × 4.67

=887.3N

Answer:

(a) 4.67 m/s²

(b) 905.42 N

Explanation:

Given:

Weight, w = 1.9 kN

       weight = mass × acceleration due to gravity

           1.9 kN = mass × 9.8 m/s²

             mass = [tex]\frac{1900}{9.8}[/tex]

                       = 193.88 kg

Initial velocity, u = 0 m/s

Final velocity, v = 87.4 km/h

converting to m/s = [tex]\frac{87.4 * 1000}{3600}[/tex] = 24.28 m/s

Time, t = 5.2 s

From equation of motion;

                      v = u + at

                    24.28 = 0 + 5.2a

                   5.2a = 24.28

                        [tex]a = \frac{24.28}{5.2}[/tex]

                        a = 4.67 m/s²

(b) From Netwon's second law of motion, the force acting on a body is equal to the product of the mass and acceleration experienced by the body.

                       F = mass × acceleration

                       F = 193.88 × 4.67

                      F = 905.42 N

                     

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