Explanation:
The given data is as follows.
Concentration difference = (1.2 - 0.8)
= 0.4
Diffusion coefficient (D) = [tex]3 \times 10^{-10} m^{2}/s[/tex]
Path length = [tex]5 \times 10^{-3}[/tex]
Relation between flux and concentration difference is as follows.
[tex]Flux = D \times \frac{\text{concentration difference}}{\text{Path length}}[/tex]
Putting the given values into the above formula as follows.
[tex]Flux = D \times \frac{\text{concentration difference}}{\text{Path length}}[/tex]
= [tex]3 \times 10^{-10} m^{2}/s \times \frac{{0.4}}{5 \times 10^{-3}}[/tex]
= [tex]\frac{1.2 \times 10^{-10}}{5 \times 10^{-3}}[/tex]
= [tex]2.4 \times 10^{-8} kg/m^{2}sec[/tex]
Thus, we can conclude that the diffusion flux of carbon through the given plate is [tex]2.4 \times 10^{-8} kg/m^{2}sec[/tex].