Answer:
24.08°
Explanation:
From Electromagnetism,
F = qBvsin∅................... Equation 1
Where F = force on the moving proton, B = magnetic Field, v = velocity of proton, ∅ = angle between proton's velocity and the field, q = charge of proton.
make ∅ the subject of the equation
∅ = sin⁻¹(F/qBv)............... Equation 2
Given: F = 7.20×10⁻¹³ N, q = 1.602 x 10⁻¹⁹ C, B = 1.72 T, v = 6.4×10⁶ m/s
Substitute into equation 2
∅ = sin⁻¹[7.20×10⁻¹³/(1.602 x 10⁻¹⁹× 1.72× 6.4×10⁶)]
∅ = sin⁻¹[0.408]
∅ = 24.08°.
Hence the angle between the velocity and the Field = 24.08°
