Answer:
1. False
2. True
3. True
Explanation:
1- False —> The relation between electric potential and electric field is given such that
[tex]-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}[/tex]
Therefore, for a uniform E field, electric potential is linearly proportional to the distance.
2- True —> The electric field lines always cross the equipotential lines perpendicularly.
3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:
[tex]V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}[/tex]
There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.