Answer:
x = [tex]\frac{6}{2y-8}[/tex] or [tex]\frac{3}{y-4}[/tex] (Note: [tex]\frac{3}{y-4}[/tex] is the simplified version)
Step-by-step explanation:
2xy - 6 = 8x Original problem
2xy - 6 + (-8x) = 8x + (-8x) Add -8x to both sides
2xy - 8x - 6 = 0
2xy-8x - 6 (+6) = 0 (+6) Add 6 to both sides
2xy - 8x = 6 .
x(2y - 8) = 6 Factor out variable x
[tex]\frac{x(2y-8)}{2y-8} =\frac{6}{2y-8}[/tex] Divide both sides by 2y - 8
x = [tex]\frac{6}{2y-8}[/tex] = [tex]\frac{3}{y-4}[/tex]
