Question

Sodium hydrogen carbonate decomposes (breaks down) to form sodium carbonate, carbon dioxide, and water. Write a skeleton equation for this reaction. Begin by identifying the reactant(s) and product(s).

Answer 1

Answer:

The equation is:

2NaHCO₃ →  Na₂CO₃  +  CO₂ + H₂O

Explanation:

We identify the reactant

NaHCO₃ → Sodium bicarbonate

We identify the products:

Na₂CO₃, CO₂ and H₂O

2 moles of sodium bicarbonate decomposes to produce 1 mol of water, carbon dioxide and sodium carbonate

Answer 2

Answer:

Reactant: Sodium hydrogen carbonate

Products: Sodium carbonate, carbon dioxide and water

Explanation:

Skeleton equations are used to represent a chemical reaction in the form of chemical formula of the compound present in the reaction.

Reactants and products are separated by arrow.

Reactants are placed on the left hand side of the arrow and products are placed on right hand side.

In the given reaction, sodium hydrogen carbonate is the reactant.

Products are sodium carbonate, carbon dioxide and water.

The balanced skeleton equation is as follows:

$2NaHCO_3\rightarrow Na_2CO_3 + CO_2+H_2O$