Question

Airplane flight recorders are made to survive horrific crashes. In an impact test to simulate a crash, the 41.0 kg box for the recorder is projected at a wall. The speed of the box is 220 m/s and the box is brought to a halt in 6.5 ms collision with the wall. (a) What is the magnitude of the average acceleration exerted on the box during the collision? (b) What is the magnitude of the average force exerted on the box during the collision (c) How many times the weight of the box is the collision force?

Answer 1

Answer:

a)a= 33486.15m/s² b) F= 1387692.307N c) Force is 3450.17 times more than weight of box

Explanation:

First we need to calculate force exerted on box during collision in order to determine acceleration.

b)

                          FΔt = mv

By rearranging it, we get

                          F = mv/Δt = (41*220)/0.0065 = 1387692.307N

a)

Now, using 2nd law of motion, we have

                         F=ma

                         a= F/m = 1387692.307/41 = 33486.15m/s²

c)

no. of times force is compared to weight of box = F/W = F/mg

                          =  1387692.307/(41*9.81) = 3450.17

Force is 3450.17 times more than weight of box