Question

Using glucose as an example of food, calculate the annual human production of CO2 in grams, assuming that each person consumes 4.35 × 102 g of glucose per day. The world's population is 6.50 billion and there are 365 days in a year.

Answer 1

Answer:

Therefore the annul human production of $CO_2$ =1.514×10¹⁵ gram

Explanation:

A glucose molecule react with oxygen and produce carbon-dioxide and water.

The reaction is

$C_6H_{12}O_6+O_2 \rightarrow CO_2+H_2O$

The balance form of the above reaction is

$C_6H_{12}O_6+6O_2 \rightarrow6 CO_2+6H_2O$

The molar mass of $C_6H_{12}O_6$ is

={(6×12)+(12×1)+(6×16)}g/mole

=180 g/mole

The molar mass of  $CO_2$ is

=[{12+(2×16)}] g/mole

=44 g/mole

Then the molar mass of 6$CO_2$ is

=(6×44) g/mole

=264 g/mole

180 gram glucose is produce 264 gram of  $CO_2$.

1 gram glucose is produce $\frac{264}{180}$ gram of  $CO_2$.

Given that each person consumes 4.32×10² g glucose per day.

Therefore each person produce $(\frac{264}{180}\times 4.35\times 10^2)$ gram $CO_2$ per day

Total population in the world is 6.50 billion= 6.50 ×10⁹

∴ 6.50 ×10⁹  produce $(\frac{264}{180}\times 4.35\times 10^2\times6.50\times10^ 9)$ gram $CO_2$ per day

Therefore the annul human production of $CO_2$

=$(\frac{264}{180}\times 4.35\times 10^2\times6.50\times10^ 9\times 365) gram$

=15136.55×10¹¹ gram

=1.514×10¹⁵ gram