Answer:
[tex]7x\sqrt[3]{x^2y}[/tex]
Step-by-step explanation:
Given:
5 x (RootIndex 3 StartRoot x squared y EndRoot) + 2 (RootIndex 3 StartRoot x Superscript 5 Baseline y EndRoot)
Algebraic expression for the given problem is
[tex]5x\sqrt[3]{x^2y} +2\sqrt[3]{x^5y}[/tex]
The second term = [tex]2\sqrt[3]{x^5y} =2\sqrt[3]{x^3*x^2*y} =2\sqrt[3]{x^3}\sqrt[3]{x^2y}=2x \sqrt[3]{x^2y}\\[/tex]
So,
[tex]5x\sqrt[3]{x^2y} +2\sqrt[3]{x^5y}[/tex]
= [tex]5x\sqrt[3]{x^2y} +2x\sqrt[3]{x^2y}[/tex] Take [tex]\sqrt[3]{x^2y}[/tex] as common
[tex]\sqrt[3]{x^2y} \ (5x+2x)\\=7x\sqrt[3]{x^2y}[/tex]
