Write the ion-product expression at equilibrium for each compound: How to enter the correct answer: e.g. silver sulfate (Ag2SO4) enter this: {Ag+}2{SO42-} don't enter spaces, use square brackets [] not {} or () for concentration and don't worry about subscripting or superscripting [ (1) magnesium carbonate (2) calcium phosphate (3) silver sulfide

Respuesta :

Answer:

(1) Magnesium carbonate :-

[tex]Q_{MgCO_3}=[Mg^{2+}][CO_3^{2-}][/tex]

(2) Calcium phosphate :-

[tex]Q_{Ca_3(PO_4)_2}=[Ca^{2+}^3][PO_4^{3-}^2][/tex]

(3) Silver sulfide :-

[tex]Q_{Ag_2S}=[Ag^{+}^2][S^{2-}][/tex]

Explanation:

(1) Magnesium carbonate will dissociate as:-

[tex]MgCO_3\rightarrow Mg^{2+}+CO_3^{2-}[/tex]

The expression for the ion-product is as follows:-

[tex]Q_{MgCO_3}=[Mg^{2+}][CO_3^{2-}][/tex]

(2) Calcium phosphate will dissociate as:-

[tex]Ca_3(PO_4)_2\rightarrow 3Ca^{2+}+2PO_4^{3-}[/tex]

The expression for the ion-product is as follows:-

[tex]Q_{Ca_3(PO_4)_2}=[Ca^{2+}^3][PO_4^{3-}^2][/tex]

(3) Silver sulfide will dissociate as:-

[tex]Ag_2S\rightarrow 2Ag^{+}+S^{2-}[/tex]

The expression for the ion-product is as follows:-

[tex]Q_{Ag_2S}=[Ag^{+}^2][S^{2-}][/tex]

ACCESS MORE
EDU ACCESS