Question

Of customers ordering a certain type of computer, 15% order an upgraded graphics card, 30% order extra memory, 20% order both the upgraded graphics card and extra memory, and 35% order neither. Fifteen orders are selected at random. Let ????1,????2,????3,????4 denote the respective number of orders in the four given categories. A. Find P(????1=3,????2=4,????3=2,????4=6).

Answer 1

Answer:

2.0104*10^(-9)

Step-by-step explanation:

Given that of customers ordering a certain type of computer, 15% order an upgraded graphics card, 30% order extra memory, 20% order both the upgraded graphics card and extra memory, and 35% order neither

15 orders are selected at random

P(x1=3, x2 =4, x3 =2 and x4 =6) where x1 , x2, x3 and x4 represent the upgraded graphics, extra memory, both and neither respectively.

Each order is independent of the other.

P(x1) = 0.15, P(X2) = 0.30 , P(x3) = 0.20 and P(x4) = 0.35

Since independent we  get

P(x1=3) = $0.15^3$

P(X2=4) = $0.3^4$

P(X3=2) = $0.2^2$

P(X4=6) = $0.35^6$

Required probability = Product of all these four

= 2.0104*10^(-9)