Answer:
Step-by-step explanation:
Let the speed of the roller coaster at the bottom is v.
radius, r = 47 m
Let the mass is m and the force at the bottom is 2.5 times the weight.
F = 2.5 mg
So, the force is
[tex]F = mg + \frac{mv^{2}}{r}[/tex]
[tex]2.5 mg= mg + \frac{mv^{2}}{r}[/tex]
[tex]1.5g=\frac{v^{2}}{r}[/tex]
v² = 1.5 gr
v² = 1.5 x 9.8 x 47
v = 26.3 m/s