Question

write the polynomial function of least degree with zeros 2 and 3i.​

Answer 1

Answer:

The answer is $x^2-(2+3i)x+6i$

Step-by-step explanation:

The polynomial with zeros 2 and 3i must have factors $(x-2)$ and $(x-3i)$ so the polynomial is

$(x-2)(x-3i)=x^2-(2+3i)x+6i$