Answer:
[tex]\dfrac{f(x+h) - f(x)}{h}=-8x-4h-3[/tex]
Step-by-step explanation:
[tex]f(x)=-4x^2-3x-4[/tex]
[tex]f(x+h)=-4(x+h)^2-3(x+h)-4[/tex]
[tex]f(x+h)=-4(x^2+2xh+h^2)-3(x+h)−4[/tex]
[tex]f(x+h)=-4x^2-8xh-4h^2-3x-3h-4[/tex]
[tex]f(x+h) - f(x)=-4x^2-8xh-4h^2-3x-3h-4-(-4x2-3x-4)[/tex]
[tex]f(x+h) - f(x)=-4x^2-8xh-4h^2-3x-3h-4+4x2+3x+4[/tex]
[tex]f(x+h) - f(x)=-8xh-4h^2-3h[/tex]
[tex]f(x+h) - f(x)=h(-8x-4h-3)[/tex]
[tex]\dfrac{f(x+h) - f(x)}{h}=\dfrac{h(-8x-4h-3)}{h}[/tex]
[tex]\dfrac{f(x+h) - f(x)}{h}=-8x-4h-3[/tex]