answer :
[tex] {x}^{2} - 3x + 1[/tex]
Step-by-step explanation:
The explanation is shown in the image
As shown in the image:
1. x divides [tex] {x}^{3}[/tex]=[tex]{x}^{2}[/tex]
2. [tex]{x}^{2}[/tex] multiplies the divisor (x-1) and we obtain [tex] {x}^{3}-{x}^{2}[/tex]
3. [tex] {x}^{3}-{x}^{2}[/tex] substracts from [tex] {x}^{3}-4{x}^{2}[/tex] leaving a remainder of [tex] -3{x}^{2}[/tex]
4. we then stepped 4x down to have [tex] -3{x}^{2}[/tex]+4x
5. x divides [tex] -3{x}^{2}[/tex] gives us -3x
6. we then multiply -3x by (x-1) and subtract it from [tex]-3{x}^{2}[/tex]+4x ,and we obtained x as a remainder
6. we again stepped the -1 down to x-1
7.x -1 divides x-1 gives exactly 1