Question

Find the distance between (5, 5) and (-5, -5).

A+LS Question

Answer 1

Answer:

Step-by-step explanation:

The formula for determining the distance between two points on a straight line is expressed as

Distance = √(x2 - x1)² + (y2 - y1)²

Where

x2 represents final value of x on the horizontal axis

x1 represents initial value of x on the horizontal axis.

y2 represents final value of y on the vertical axis.

y1 represents initial value of y on the vertical axis.

From the information given,

x2 = - 5

x1 = 5

y2 = - 5

y1 = 5

Therefore,

Distance = √(- 5 - 5)² + (- 5 - 5)²

Distance = √- 10² + - 10² = √100 + 100 = √200

Distance = 14.14

Answer 2

Answer:

10√2

Step-by-step explanation:

P1 (5,5)= point 1

P2 (-5,-5) = point 2

eucliedean distance between two points is defined as

D(P1,P2) = $\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

order does not matter, you can invert the terms x and y, as even if the subtraction gives a negative result, you are squaring it

so D(P1,P2) = $\sqrt{(5-(-5))^2+(5-(-5))^2}$ = $\sqrt{10^2+10^2}$ = $\sqrt{2*10^2}$ = 10√2 ≅14.14