Question

. For vectors B⃗ =−iˆ−4jˆB→=−i^−4j^ and A⃗ =−3iˆ−2jˆA→=−3i^−2j^ , calculate (a) A⃗ +B⃗ A→+B→ and its magnitude and direction angle, and (b) A⃗ −B⃗ A→−B→ and its magnitude and direction angle.

Answer 1

Answer:

Step-by-step explanation:

given are two vectors

$B=-i-4j\\A = 3i-2j$

a) A+B = sum of twovectors = simply adding corrsponding compnents

=$2i-6j$

Magnitude of the above vector = $\sqrt{2^2+6^2} \\=2\sqrt{10}$

Direction is making an angle of arc tan (-3) with x axis

b) A-B = Difference

= $4i+2j$

Magnitude of difference vector = $\sqrt{4^2+2^2} \\=2\sqrt{5}$

Direction is making an angle of arctan (1/2) with positive x axis.

(angle = arctan (jcomponent/icomponent)