The Function h(x) is defined as shown. What is the range of h(x)?

Answer:
[tex]h(x)\leq 5[/tex]
Step-by-step explanation:
Piecewise Function
The given function has a point where its behavior changes. At the left side of x=3 the function is
[tex]h(x)=x+2[/tex]
While at the right side the function is
[tex]h(x)=-x+8[/tex]
We need to find the range of h, i.e. the values h takes when x moves along its domain. Let's analyze what values takes h when x decreases without limit.
[tex]\lim\limits_{x \rightarrow -\infty }(x+2)=-\infty[/tex]
When x=3
[tex]h(3)=-3+8=5[/tex]
When x increses without limit
[tex]\lim\limits_{x \rightarrow \infty }(-x+8)=-\infty[/tex]
As shown, the values of h run from [tex]-\infty[/tex] to 5, i.e.
[tex]Range \ h=(-\infty , 5][/tex]
Or, equivalently
[tex]\boxed{h(x)\leq 5}[/tex]
Answer:
h(x) ≤ 5 is the corrects answer
Step-by-step explanation:
I got it right on EDG