Respuesta :

Answer:

[tex]h(x)\leq 5[/tex]

Step-by-step explanation:

Piecewise Function

The given function has a point where its behavior changes. At the left side of x=3 the function is

[tex]h(x)=x+2[/tex]

While at the right side the function is

[tex]h(x)=-x+8[/tex]

We need to find the range of h, i.e. the values h takes when x moves along its domain. Let's analyze what values takes h when x decreases without limit.

[tex]\lim\limits_{x \rightarrow -\infty }(x+2)=-\infty[/tex]

When x=3

[tex]h(3)=-3+8=5[/tex]

When x increses without limit

[tex]\lim\limits_{x \rightarrow \infty }(-x+8)=-\infty[/tex]

As shown, the values of h run from [tex]-\infty[/tex] to 5, i.e.

[tex]Range \ h=(-\infty , 5][/tex]

Or, equivalently

[tex]\boxed{h(x)\leq 5}[/tex]

Answer:

h(x) ≤ 5 is the corrects answer

Step-by-step explanation:

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