Question

The average number of loaves of bread put on a shelf in a bakery in a half-hour period is 12. Of interest is the number of loaves of bread put on the shelf in five minutes. The time interval of interest is five minutes. What is the probability that the number of loaves, selected randomly, put on the shelf in five minutes is Two

Answer 1

Answer:

0.271

Step-by-step explanation:

Poisson Distribution

30 mins : 12

5 mins : 2 loaves

X ~ Po(2)

(e^-2)(2²/2!) = 0.2706705665

= 0.271 (3 sf)

Answer 2

Hence probability becomes= 0.271 (3 sf)=271/1000

What is Poisson distribution?

The Poisson distribution is a discrete distribution that calculates the likelihood of a certain number of events occurring in a particular time period.

P(x; ) = (e-) (x) / x! is the Poisson Distribution formula.

How to solve ?

Given The average number of loaves of bread put on a shelf in a bakery in a half-hour period is 12

Of interest is the number of loaves of bread put on the shelf in five minutes. .

The time interval of interest is five minutes. To solve probability we use Poisson distribution.

Hence applying Poisson Distribution

=30 mins : 12

=5 mins : 2 loaves

=X ~ Po(2)

=(e^-2)(2²/2!) = 0.2706705665

= 0.271 (3 sf)=271/1000

Learn more about Poisson Distribution

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