Answer:
The mean of the sampling distribution of sample proportion is the population proportion p.
Step-by-step explanation:
According to the central limit theorem, if a large sample (n > 30) is selected from an unknown population with population proportion p, then the sampling distribution of sample proportion follows a Normal distribution.
The mean and standard deviation of the sampling distribution of sample proportion is:
[tex]\mu_{\hat p}=p\\\sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}}[/tex]
Thus, the mean of the sampling distribution of sample proportion is the population proportion p.
