Question

Which ordered pair is a solution of the inequality y < 3x + 1?
A. (-3, -2)
B. (3, 14)
C. (1, -3)
D. (1,6)

Answer 1

Answer:

C

Step-by-step explanation:

y<3x+1

let x=1, let y=-3

-3<3(1)+1

-3<4

C is able to satisfy the formula

Answer 2

The solutions of an inequality are the true values of the inequality.

The solution of $\mathbf{y < 3x + 1}$ is (1, -3)

The inequality is given as:

$\mathbf{y < 3x + 1}$

Start by testing the options

(A) (-3, -2)

This gives

$\mathbf{-2 < 3(-3) + 1}$

$\mathbf{-2 < -9 + 1}$

$\mathbf{-2 < -8}$

This is false, because $\mathbf{-2 > -8}$

(B) (3, 14)

This gives

$\mathbf{14 < 3(3) + 1}$

$\mathbf{14 < 9 + 1}$

$\mathbf{14 < 10}$

This is false, because $\mathbf{14 > 10}$

(C) (1, -3)

This gives

$\mathbf{-3 < 3(1) + 1}$

$\mathbf{-3 < 3 + 1}$

$\mathbf{-3 < 4}$

This is true, because $\mathbf{-3 < 4}$

Hence, the solution of $\mathbf{y < 3x + 1}$ is (1, -3)

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