Answer:
51.1°C
Explanation:
Parameters given:
Mass of water = 2410g = 2.41 kg
Heat absorbed = 4.95 * 10^5 J
The formula for heat capacity in terms of mass, specific heat capacity and temperature is given as:
H = mC(T2 - T1)
Where m = mass
C = specific heat capacity of water = 4200 J/kg°C
T2 = final temperature
T1 = initial temperature
In this case, the final temperature is 100°C since the water boils, hence, to find T1,
4.95 * 10^5 = 2.41 * 4290 * (100 - T1)
=> 100 - T1 = 495000/(2.41 * 4200)
100 - T1 = 48.9
=> T1 = 100 - 48.9
T1 = 51.1°C
The initial temperature of the water was 51.1°C
