Question

An Olympic pole vaulter's height can be modeled by the equation f(x) = −16x^2 + 32x, where x is the time in seconds after the vaulter leaves the ground. Find the vaulter's maximum height and the time it takes the vaulter to reach this height. Then find how long the vaulter is in the air.

Answer 1

Answer:

At 1 second, the vaulter has reached a maximum height of 16 feet. The vaulter is in the air for 2 seconds.

Step-by-step explanation:

The vaulter's maximum height is 16 ft and it takes 1 s to reach this height.

The vaulter takes the same time to fall back to the ground. Therefore the vaulter is in the air for 2 s.