Question

What net force (in N) is acting on her if she is standing on an amusement park merry-go-round that rotates at 2.8 rpm and she is 6.1 m from its center?

Answer 1

Answer:

Force, F = 10.51 N

Explanation:

Given that,

The angular speed of the merry-go-round, $\omega=2.8\ rpm=0.29\ rad/s$

Distance from the center, r = 6.1 m

We need to find the net force acting on the girl if she is moving in merry-go-round. The force acting on her is called the centripetal force. It is given by :

Let the mass of the girl is, m = 20.5 kg

The force is given by :

$F=m\omega^2r$

$F=20.5\times 0.29^2\times 6.1$

F = 10.51 N

So, the force acting on the girl is 10.51 N. Hence, this is the required solution.