Answer:
The probability of an incorrect report is found to be 0.03 or 3%.
Explanation:
We will get an incorrect report in both the cases of false alarm or missing excessive radiation. Since, both are mutually exclusive events. Therefore, the probability of both events to occur simultaneously will be 0. Thus, the probability of an incorrect report will be the sum of the probability of false alarm and the probability of a missing radiation.
P (False Alarm) = 0.02
P (Missing Radiation) = 0.01
P(Incorrect Report) = P (False Alarm) + P(Missing Radiation)
P (Incorrect Report) = 0.02 +0.01
P(Incorrect Report) = 0.03 = 3%