Answer:
[tex]z=1.0152x - 2538.07[/tex]
where [tex]x[/tex] is the total expenses and [tex]z[/tex] is the required loan needed to incur to cover all school expenses including the loan fee.
Explanation:
If total expenses is [tex]x[/tex], required loan is [tex]z[/tex] and loan charge is [tex]y[/tex], we can deduce the following relationship from the given: there is already a savings of $2500, therefore, the total expenses must be at least equal to savings plus loan minus loan charge i.e.
[tex]x=2500+(z-y)[/tex]..........................................eq(1)
but
[tex]y=1.5% of z[/tex]% of [tex]z[/tex]
[tex]y=0.015z[/tex]..............................................eq(2)
substituting [tex]y[/tex] in eq(2) into eq(1), we have
[tex]x=2500+(z-0.0152z)\\x=2500+0.985z[/tex]
rearranging,
[tex]z=\frac{x-2500}{0.985}[/tex][tex]=1.0152x-2538.07[/tex]
∵[tex]z=1.0152x-2538.07[/tex]..........................(3)
For example: suppose the total expenses [tex]x[/tex] is $4000, the required loan [tex]z[/tex] will be calculated as follows-
Applying equation 3,
[tex]z=1.0152*4000-2538.07[/tex]=$[tex]1522.73[/tex]
To test the outcome of the model, compare to see if the sum of savings and required loan is greater than or equal to total expenses.
[tex]z+2500>x[/tex]
$1522.73+$2500>4000 i.e.
$4022.73>4000 this show that the expenses can be taken care of by the loan and the savings