Question

What is the result when 6x3 – 3x2 – 28x + 2 is divided by 2x – 5? If there is a
remainder, express the result in the form q(x) + 2).

Answer 1

Answer:

-2.4-14(x)

Step-by-step explanation:

6*3-3*2-28x/2x-5=

18-6-28x/2x-5=

12-28x/2x-5=

-2.4-14(x)

Answer 2

Answer:  $\bold{3x^2+6x+1+\dfrac{3}{6x^3-3x^2-28x+2}}$

Step-by-step explanation:

Use long division

$.\qquad \ \underline{\quad 3x^2+6x+1\quad \qquad }\\2x-5 )6x^3-3x^2-28x+2\\.\ \quad -\underline{(6x^3-15x^2)}\quad \downarrow \quad \ \downarrow\\.\ \qquad \qquad \quad 12x^2-28x\ \ \downarrow\\.\quad \quad \quad \ \ -\underline{(12x^2-30x)}\ \downarrow\\.\qquad \qquad \qquad \qquad \ \ 2x+2\\.\qquad \qquad \qquad \quad -\underline{(2x-5)}\\.\qquad \qquad \qquad \qquad \qquad \quad 3\\\\.\quad \large\boxed{3x^2+6x+1+\dfrac{3}{6x^3-3x^2-28x+2}}$